![An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10.0 ^o C to 15.0 ^o C in 100 s. Calculate the specific heat capacity of liquid: An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10.0 ^o C to 15.0 ^o C in 100 s. Calculate the specific heat capacity of liquid:](https://dwes9vv9u0550.cloudfront.net/images/1756438/43622bca-895e-4778-b838-a394032c34ba.jpg)
An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10.0 ^o C to 15.0 ^o C in 100 s. Calculate the specific heat capacity of liquid:
![SOLVED: The enthalpy of air is increased by 139.586 kJ.kg in a compressor. The rate of air flow is 16.42 kg/min. The power input is 48.2 kW. Determine the heat loss in SOLVED: The enthalpy of air is increased by 139.586 kJ.kg in a compressor. The rate of air flow is 16.42 kg/min. The power input is 48.2 kW. Determine the heat loss in](https://cdn.numerade.com/ask_previews/7817b963-e75e-48db-8d27-9d9e9afacdf6_large.jpg)
SOLVED: The enthalpy of air is increased by 139.586 kJ.kg in a compressor. The rate of air flow is 16.42 kg/min. The power input is 48.2 kW. Determine the heat loss in
Chapter two Conservation of Energy and The first Law of Thermodynamics Principle of energy conservation:- State that energy can
![Helium is to be compressed from 105 kPa and 295 K to 700 kPa and 460K. A heat loss of 15 kJ/kg occurs during the compression process. Neglecting kinetic energy changes, determine Helium is to be compressed from 105 kPa and 295 K to 700 kPa and 460K. A heat loss of 15 kJ/kg occurs during the compression process. Neglecting kinetic energy changes, determine](https://homework.study.com/cimages/multimages/16/08.16.205555847402390262513.jpg)
Helium is to be compressed from 105 kPa and 295 K to 700 kPa and 460K. A heat loss of 15 kJ/kg occurs during the compression process. Neglecting kinetic energy changes, determine
![PDF) APPLIED THERMODYNAMICS D201 SELF ASSESSMENT SOLUTIONS TUTORIAL 1 | Deepak Sharma - Academia.edu PDF) APPLIED THERMODYNAMICS D201 SELF ASSESSMENT SOLUTIONS TUTORIAL 1 | Deepak Sharma - Academia.edu](https://0.academia-photos.com/attachment_thumbnails/32404870/mini_magick20180818-7156-6bpdp2.png?1534649521)
PDF) APPLIED THERMODYNAMICS D201 SELF ASSESSMENT SOLUTIONS TUTORIAL 1 | Deepak Sharma - Academia.edu
![Thermodynamics 1 - KJ kg−k Sact<Ssat:wet¿get x:Sact=sf+xsfg5.2=2+x(4) x=0¿68% 2. At 10m3 vessel - Studocu Thermodynamics 1 - KJ kg−k Sact<Ssat:wet¿get x:Sact=sf+xsfg5.2=2+x(4) x=0¿68% 2. At 10m3 vessel - Studocu](https://d20ohkaloyme4g.cloudfront.net/img/document_thumbnails/34e28fba68507a643e7250b3d8eef926/thumb_1200_1553.png)